1.Let x(t)=22costsin2tx(t) = 2\sqrt{2} \cos t \sqrt{\sin 2t}x(t)=22costsin2t and y(t)=22sintsin2ty(t) = 2\sqrt{2} \sin t \sqrt{\sin 2t}y(t)=22sintsin2t, t∈(0,π2)t \in \left(0, \frac{\pi}{2}\right)t∈(0,2π). Then 1+(dydx)2d2ydx2\frac{1 + \left(\frac{dy}{dx}\right)^2}{\frac{d^2y}{dx^2}}dx2d2y1+(dxdy)2 at t=π4t = \frac{\pi}{4}t=4πis equal toa.−223\frac{-2\sqrt{2}}{3}3−22b.23\frac{2}{3}32c.13\frac{1}{3}31d.−23\frac{-2}{3}3−2Login to continueOnly logged in users canattempt or see the solution.
