1.A cup of coffee cools from 90∘C90^\circ\text{C}90∘C to 80∘C80^\circ\text{C}80∘C in ttt minutes, when the room temperature is 20∘C20^\circ\text{C}20∘C. The time taken by a similar cup of coffee to cool from 80∘C80^\circ\text{C}80∘C to 60∘C60^\circ\text{C}60∘C at a room temperature same at 20∘C20^\circ\text{C}20∘C is:a.103t\frac{10}{3}t310tb.113t\frac{11}{3}t311tc.109t\frac{10}{9}t910td.143t\frac{14}{3}t314tLogin to continueOnly logged in users canattempt or see the solution.