1.If α\alphaα and β\betaβ are the roots of the equation 7x2−3x−2=07x^2 - 3x - 2 = 07x2−3x−2=0, then the value of αβ2+1α\dfrac{\alpha}{\beta^2} + \dfrac{1}{\alpha}β2α+α1 is equal to:a.278\dfrac{27}{8}827b.12\dfrac{1}{2}21c.38\dfrac{3}{8}83d.278\dfrac{27}{8}827Login to continueOnly logged in users canattempt or see the solution.
