1.limx→02x∣x∣+x2=\displaystyle\lim_{x\to0}\frac{2x}{|x|+x^2}=x→0lim∣x∣+x22x=a.Limit existsb.Limit does not existc.222d.−2-2−2Login to continueOnly logged in users canattempt or see the solution.
