1.Two particles of equal mass mmm go round a circle of radius RRR under the action of their mutual gravitational attraction. The speed of each particle is:a.GmR\sqrt{\frac{Gm}{R}}RGmb.4GmR\sqrt{\frac{4Gm}{R}}R4Gmc.Gm2R\frac{Gm}{2R}2RGmd.12GmR\frac{1}{2}\sqrt{\frac{Gm}{R}}21RGmLogin to continueOnly logged in users canattempt or see the solution.