1.Solubility product of AgBr is 4.9×10−134.9 \times 10^{-13}4.9×10−13. What is its solubility in mol dm−3^{-3}−3?a.2.4×10−72.4 \times 10^{-7}2.4×10−7b.3.2×10−73.2 \times 10^{-7}3.2×10−7c.4.9×10−74.9 \times 10^{-7}4.9×10−7d.7.0×10−77.0 \times 10^{-7}7.0×10−7Login to continueOnly logged in users canattempt or see the solution.
