1.
Let the determinant of a square matrix AA of order mm be mnmn, where mm and nn satisfy 4m+n=224m + n = 22 and 17m+4n=9317m + 4n = 93. If nadj(adj(mA))=3a5b6c\left|n\,\text{adj}\bigl(\text{adj}(mA)\bigr)\right| = 3^{a}\cdot 5^{b}\cdot 6^{c}, then a+b+ca + b + c is equal to: