1.Equation of circle through origin cutting x2+y2−6x+8=0x^2+y^2-6x+8=0x2+y2−6x+8=0 and x2+y2−2x−2y=7x^2+y^2-2x-2y=7x2+y2−2x−2y=7 orthogonallya.3x2+3y2−8x−13y=03x^2+3y^2-8x-13y=03x2+3y2−8x−13y=0b.3x2+3y2−8x+29y=03x^2+3y^2-8x+29y=03x2+3y2−8x+29y=0c.3x2+3y2+8x+29y=03x^2+3y^2+8x+29y=03x2+3y2+8x+29y=0d.3x2+3y2−8x−29y=03x^2+3y^2-8x-29y=03x2+3y2−8x−29y=0Login to continueOnly logged in users canattempt or see the solution.
