1.For the natural numbers m,nm, nm,n, if (1−y)m(1+y)n=1+a1y+a2y2+⋯+am+nym+n(1-y)^m (1+y)^n = 1 + a_1 y + a_2 y^2 + \cdots + a_{m+n} y^{m+n}(1−y)m(1+y)n=1+a1y+a2y2+⋯+am+nym+n and a1=a2=10a_1 = a_2 = 10a1=a2=10, then the value of m+nm + nm+n, is equal to:a.88b.64c.100d.80Login to continueOnly logged in users canattempt or see the solution.
