1.Let a1,a2,a3,…a_1, a_2, a_3, \dotsa1,a2,a3,… be a G.P. of increasing positive numbers. Let the sum of its 6th6^{\text{th}}6th and 8th8^{\text{th}}8th terms be 222 and the product of its 3rd3^{\text{rd}}3rd and 5th5^{\text{th}}5th terms be 19\dfrac{1}{9}91. Then 6(a2+a4)(a4+a6)6(a_2 + a_4)(a_4 + a_6)6(a2+a4)(a4+a6) is equal to:a.333b.333\sqrt{3}33c.222d.222\sqrt{2}22Login to continueOnly logged in users canattempt or see the solution.