1.If f(x)=3[x]+{x+1}f(x) = 3[x] + \{x+1\}f(x)=3[x]+{x+1}, where [x][x][x] is greatest integer function of xxx and {x}\{x\}{x} is fractional part function of xxx, then f(−1.32)=f(-1.32) =f(−1.32)=a.−4.6-4.6−4.6b.−2.6-2.6−2.6c.−7.4-7.4−7.4d.−3.4-3.4−3.4Login to continueOnly logged in users canattempt or see the solution.
