1.If (201)⋅12+(202)⋅22+(203)⋅32+⋯+(2020)⋅202=A⋅2B\binom{20}{1} \cdot 1^{2} + \binom{20}{2} \cdot 2^{2} + \binom{20}{3} \cdot 3^{2} + \cdots + \binom{20}{20} \cdot 20^{2} = A \cdot 2^{B}(120)⋅12+(220)⋅22+(320)⋅32+⋯+(2020)⋅202=A⋅2B, then the ordered pair (A,B)(A, B)(A,B) is equal toa.(380,19)(380, 19)(380,19)b.(420,18)(420, 18)(420,18)c.(420,19)(420, 19)(420,19)d.(380,18)(380, 18)(380,18)Login to continueOnly logged in users canattempt or see the solution.
