1.A die is thrown two times and the sum of the scores appearing on the die is observed to be a multiple of 444. Then the conditional probability that the score 444 has appeared at least once is:a.13\dfrac{1}{3}31b.29\dfrac{2}{9}92c.14\dfrac{1}{4}41d.19\dfrac{1}{9}91Login to continueOnly logged in users canattempt or see the solution.