1.If α=sin−1(13)+sin−1(1?)\alpha = \sin^{-1}\left(\frac{1}{3}\right) + \sin^{-1}\left(\frac{1}{?}\right)α=sin−1(31)+sin−1(?1) and β=cos−1(??)+cos−1(??)\beta = \cos^{-1}\left(\frac{?}{?}\right) + \cos^{-1}\left(\frac{?}{?}\right)β=cos−1(??)+cos−1(??), thena.α>β\alpha > \betaα>βb.α=β\alpha = \betaα=βc.α<β\alpha < \betaα<βd.αβ=2π\alpha\beta = 2\piαβ=2πLogin to continueOnly logged in users canattempt or see the solution.
