1.For α,β∈R\alpha, \beta \in \mathbb{R}α,β∈R and a natural number nnn, letAr=∣r1n22+α2r2n2−β3r−23n(3n−1)2∣A_r = \begin{vmatrix} r & 1 & \dfrac{n^2}{2} + \alpha \\ 2r & 2 & n^2 - \beta \\ 3r-2 & 3 & \dfrac{n(3n-1)}{2} \end{vmatrix}Ar=r2r3r−21232n2+αn2−β2n(3n−1)Then 2A10−A52A_{10} - A_52A10−A5 is:a.4α+2β4\alpha + 2\beta4α+2βb.2α+4β2\alpha + 4\beta2α+4βc.000d.2n2n2nLogin to continueOnly logged in users canattempt or see the solution.
