1.The integrating factor of the differential equation (2x+3y2)dy=y dx(2x + 3y^2) dy = y\,dx(2x+3y2)dy=ydx (y>0y > 0y>0) isa.−1y2-\frac{1}{y^2}−y21b.1y2\frac{1}{y^2}y21c.e1/ye^{1/y}e1/yd.1x\frac{1}{x}x1Login to continueOnly logged in users canattempt or see the solution.