1.e1,e2e_1,e_2e1,e2 are eccentricities of 3x2−3y2=253x^2-3y^2=253x2−3y2=25 and its conjugate. Thena.e12+e22=2e_1^2+e_2^2=2e12+e22=2b.e12+e22=4e_1^2+e_2^2=4e12+e22=4c.e1+e2=4e_1+e_2=4e1+e2=4d.e1+e2=2e_1+e_2=\sqrt{2}e1+e2=2Login to continueOnly logged in users canattempt or see the solution.
