1.If f(x)={x2+3x−10x2+2x−15x≠−5ax=−5f(x)=\begin{cases}\frac{x^2+3x-10}{x^2+2x-15}&x\neq-5\\a&x=-5\end{cases}f(x)={x2+2x−15x2+3x−10ax=−5x=−5 is continuous at x=−5x=-5x=−5, then aaa isa.3/23/23/2b.7/87/87/8c.8/78/78/7d.2/32/32/3Login to continueOnly logged in users canattempt or see the solution.
