1.f(x)={x2+bx+c,x<1x,x≥1f(x)=\begin{cases}x^2+bx+c,&x<1\\x,&x\ge1\end{cases}f(x)={x2+bx+c,x,x<1x≥1 diff at 111, b−c=b-c=b−c=a.-2b.0c.1d.2Login to continueOnly logged in users canattempt or see the solution.
