1.If x=a(cost+logtant2)x = a(\cos t + \log \tan \frac{t}{2})x=a(cost+logtan2t), y=asinty = a \sin ty=asint, then dydx=\frac{dy}{dx} =dxdy=a.tant\tan ttantb.cott\cot tcottc.−cott- \cot t−cottd.tant\tan ttantLogin to continueOnly logged in users canattempt or see the solution.
