1.The escape velocity on the surface of the earth is vev_eve. If MMM and RRR are the mass and radius of the earth respectively, then the escape velocity on another planet of mass 2M2M2M and radius R2\dfrac{R}{2}2R isa.4ve4v_e4veb.2ve2v_e2vec.vev_eved.ve2\dfrac{v_e}{2}2veLogin to continueOnly logged in users canattempt or see the solution.