1.limx→0sin(πcos2x)x2\displaystyle\lim_{x\to0}\frac{\sin(\pi\cos^2x)}{x^2}x→0limx2sin(πcos2x) is equal toa.−π-\pi−πb.π\piπc.π/2\pi/2π/2d.111Login to continueOnly logged in users canattempt or see the solution.
