1.For three positive integers p,q,rp, q, rp,q,r, xpq2=y=zp2x^{pq^2} = y = z^{p^2}xpq2=y=zp2 and r=pq+1r = pq + 1r=pq+1 such that 3,3logxy,3logyz,7logzx3, 3\log_x y, 3\log_y z, 7\log_z x3,3logxy,3logyz,7logzx are in A.P. with common difference 111. Then r−p−qr - p - qr−p−q is equal toa.222b.666c.121212d.−6-6−6Login to continueOnly logged in users canattempt or see the solution.
