1.x∫1xy(t)dt=(x+1)∫1xty(t)dtx\int_1^x y(t)dt = (x+1)\int_1^x t y(t)dtx∫1xy(t)dt=(x+1)∫1xty(t)dt, x≠0x\ne0x=0. Then y(x)=y(x)=y(x)= (C constant)a.Cx3e1/xCx^3 e^{1/x}Cx3e1/xb.Cx2e−1/x\frac{C}{x^2}e^{-1/x}x2Ce−1/xc.Cxe−1/x\frac{C}{x}e^{-1/x}xCe−1/xd.Cx3e−1/x\frac{C}{x^3}e^{-1/x}x3Ce−1/xLogin to continueOnly logged in users canattempt or see the solution.