Let $B = \begin{pmatrix} 1 & 3 & \alpha \\ 1 & 2 & 3 \\ \alpha & \alpha & 4 \end{pmatrix}$, with $\alpha > 2$, be the adjoint of a $3\times 3$ matrix $A$ and $|A| = 2$. Then $\left|\begin{pmatrix} \alpha & -2\alpha & \alpha \\ -2\alpha & \alpha & \alpha \\ \alpha & \alpha & \alpha \end{pmatrix}\right| \cdot |B - 2\alpha\,I|$ is equal to: