1.Let [t][t][t] denote the greatest integer ≤t\le t≤t and limx→0[x4]=A\lim_{x \to 0} \left[ \frac{x}{4} \right] = Alimx→0[4x]=A. Then the function f(x)=[x2]sin(πx)f(x) = [x^2] \sin(\pi x)f(x)=[x2]sin(πx) is discontinuous when xxx is equal to:a.A+1\sqrt{A} + 1A+1b.A+5\sqrt{A} + 5A+5c.A+21\sqrt{A} + 21A+21d.A\sqrt{A}ALogin to continueOnly logged in users canattempt or see the solution.
