1.A particle moves along the path y=Cx6y = \dfrac{C}{x^6}y=x6C, where CCC is a positive constant. The relation between the acceleration magnitude aaa and the speed vvv of the particle at t=5t = 5t=5 s isa.5a=v5a = v5a=vb.a=5va = 5va=5vc.a=va = \sqrt{v}a=vd.a=v2a = v^2a=v2Login to continueOnly logged in users canattempt or see the solution.