Formation of polyethylene from calcium carbide takes place as follows:

$\text{CaC}_2 + 2\text{H}_2\text{O} \rightarrow \text{Ca(OH)}_2 + \text{C}_2\text{H}_2$
$\text{C}_2\text{H}_2 + \text{H}_2 \rightarrow \text{C}_2\text{H}_4$
$n\text{C}_2\text{H}_4 \rightarrow (-\text{CH}_2-\text{CH}_2-)_n$

The amount of polyethylene obtained from 64.1 kg of $\text{CaC}_2$ is