1.Let f(x)={x2+4:x<04−2x:x≥0f(x) = \begin{cases} x^2 + 4 & : x < 0 \\ 4 - 2x & : x \geq 0 \end{cases}f(x)={x2+44−2x:x<0:x≥0, then the area bounded by y=f(x)y = f(x)y=f(x) and the xxx-axis from x=−1x = -1x=−1 to x=3x = 3x=3 is equal toa.999 sq. unitsb.283\frac{28}{3}328 sq. unitsc.293\frac{29}{3}329 sq. unitsd.272727 sq. unitsLogin to continueOnly logged in users canattempt or see the solution.
