1.An electron beam travels with a velocity of 1.6×107 ms−11.6 \times 10^7\,\text{ms}^{-1}1.6×107ms−1 perpendicularly to magnetic field of intensity 0.1 T0.1\,\text{T}0.1T. The radius of the path of the electron beam (me=9×10−31 kgm_e = 9 \times 10^{-31}\,\text{kg}me=9×10−31kg)a.9×10−5 m9 \times 10^{-5}\,\text{m}9×10−5mb.9×10−2 m9 \times 10^{-2}\,\text{m}9×10−2mc.9×10−4 m9 \times 10^{-4}\,\text{m}9×10−4md.9×10−3 m9 \times 10^{-3}\,\text{m}9×10−3mLogin to continueOnly logged in users canattempt or see the solution.