1.Let a1,a2,a3,…a_1, a_2, a_3, \ldotsa1,a2,a3,… be a G.P. such that a1<0a_1 < 0a1<0, a1+a2=4a_1 + a_2 = 4a1+a2=4 and a3a4=16a_3 a_4 = 16a3a4=16. If ∑i=1∞ai2=4A\sum\limits_{i=1}^{\infty} a_i^2 = 4Ai=1∑∞ai2=4A, then AAA is equal toa.−513-513−513b.−171-171−171c.171171171d.511511511Login to continueOnly logged in users canattempt or see the solution.