1.Let rrr be a root of the equation x2+2x+6=0x^2+2x+6=0x2+2x+6=0. The value of (r+2)(r+3)(r+4)(r+5)(r+2)(r+3)(r+4)(r+5)(r+2)(r+3)(r+4)(r+5) is equal toa.515151b.−51-51−51c.−126-126−126d.126126126Login to continueOnly logged in users canattempt or see the solution.
