1.If f(x)=x2sin1xf(x)=x^2\sin\frac1xf(x)=x2sinx1 for x≠0x\neq0x=0 and f(0)=0f(0)=0f(0)=0, then limx→0f′(x)\displaystyle\lim_{x\to0}f'(x)x→0limf′(x)a.Does not existb.000c.∞\infty∞d.111Login to continueOnly logged in users canattempt or see the solution.
