1.
If for some m,nm, n, (6m)+2(6m+1)+(6m+2)>(83)\binom{6}{m} + 2\binom{6}{m+1} + \binom{6}{m+2} > \binom{8}{3} and nP3mP1=18\dfrac{{}^nP_3}{{}^mP_1} = \dfrac{1}{8}, then nm+1P1+2m+1(m1)n \cdot {}^{m+1}P_1 + 2^{m+1} \cdot \binom{m}{1} is equal to