1.limn→∞(12n3+13+22n3+23+…+n2n3+n3)=\displaystyle\lim_{n\to\infty}\left(\frac{1^2}{n^3+1^3}+\frac{2^2}{n^3+2^3}+\ldots+\frac{n^2}{n^3+n^3}\right)=n→∞lim(n3+1312+n3+2322+…+n3+n3n2)=a.log2\log2log2b.2log22\log22log2c.12log2\frac12\log221log2d.log23\log\sqrt[3]{2}log32Login to continueOnly logged in users canattempt or see the solution.
