1.The number of electrons to balance the following equation, NO3−+4H++e−→2H2O+NO\mathrm{NO_3^-} + 4\mathrm{H^+} + e^- \rightarrow 2\mathrm{H_2O} + \mathrm{NO}NO3−+4H++e−→2H2O+NO is:a.555b.444c.333d.222Login to continueOnly logged in users canattempt or see the solution.
