1.If ∣x+1xxxx+λxxxx+12∣=103x+81\begin{vmatrix} x+1 & x & x \\ x & x+\lambda & x \\ x & x & x+12 \end{vmatrix} = 103x + 81x+1xxxx+λxxxx+12=103x+81, then λ\lambdaλ and the roots of the equation are:a.4x2+24x−27=04x^2 + 24x - 27 = 04x2+24x−27=0b.4x2−24x−27=04x^2 - 24x - 27 = 04x2−24x−27=0c.4x2+24x+27=04x^2 + 24x + 27 = 04x2+24x+27=0d.4x2−24x+27=04x^2 - 24x + 27 = 04x2−24x+27=0Login to continueOnly logged in users canattempt or see the solution.
