In the lead storage battery, the anode reaction is $\mathrm{Pb(s) + HSO_4^- + H_2O \rightarrow PbSO_4(s) + H_3O^+ + 2e^-}$. How many grams of Pb will be used up to deliver $1\,\text{A}$ for $100\,\text{h}$? ($\mathrm{Pb} = 208$)