1.The centre of the ellipse (x+y−3)29+(x−y+1)216=1\frac{(x+y-3)^2}{9} + \frac{(x-y+1)^2}{16} = 19(x+y−3)2+16(x−y+1)2=1 isa.(−1,2)(-1, 2)(−1,2)b.(1,−2)(1, -2)(1,−2)c.(−1,−2)(-1, -2)(−1,−2)d.(1,2)(1, 2)(1,2)Login to continueOnly logged in users canattempt or see the solution.
