1.If f:[0,π/2)→Rf : [0, \pi/2) \to \mathbb{R}f:[0,π/2)→R is defined as f(θ)=∣1tanθ1−tanθ1tanθ−1−tanθ1∣f(\theta) = \begin{vmatrix} 1 & \tan\theta & 1 \\ -\tan\theta & 1 & \tan\theta \\ -1 & -\tan\theta & 1 \end{vmatrix}f(θ)=1−tanθ−1tanθ1−tanθ1tanθ1, then the range of fff isa.(2,∞)(2, \infty)(2,∞)b.(−∞,−2](-\infty, -2](−∞,−2]c.[2,∞)[2, \infty)[2,∞)d.(−∞,2](-\infty, 2](−∞,2]Login to continueOnly logged in users canattempt or see the solution.
