1.If limx→0((a−n)nx−tanx)sinnxx2=0\displaystyle\lim_{x\to0}\frac{((a-n)nx-\tan x)\sin nx}{x^2}=0x→0limx2((a−n)nx−tanx)sinnx=0, (n≠0)(n\neq0)(n=0), then min possible positive aaa isa.000b.−2-2−2c.222d.111Login to continueOnly logged in users canattempt or see the solution.