1.Four persons can hit a target correctly with probabilities 12\frac{1}{2}21, 13\frac{1}{3}31, 14\frac{1}{4}41 and 18\frac{1}{8}81 respectively. If all hit at the target independently, then the probability that the target would be hit, is:a.25192\frac{25}{192}19225b.1192\frac{1}{192}1921c.2532\frac{25}{32}3225d.732\frac{7}{32}327Login to continueOnly logged in users canattempt or see the solution.