1.Let mmm and nnn be the coefficients of the seventh and thirteenth terms respectively in the expansion of (12x2+13x)18\left(\frac{1}{2}x^2 + \frac{1}{3x}\right)^{18}(21x2+3x1)18. Then mn\frac{m}{n}nm is:a.1126⋅33\frac{11}{2^6 \cdot 3^3}26⋅3311b.11\frac{1}{1}11c.52\frac{5}{2}25d.11⋅3326\frac{11 \cdot 3^3}{2^6}2611⋅33Login to continueOnly logged in users canattempt or see the solution.