1.
If the matrix A=(100020301)A = \begin{pmatrix} 1 & 0 & 0 \\ 0 & 2 & 0 \\ 3 & 0 & -1 \end{pmatrix} satisfies the equation A20+αA19+βA=(100040001)A^{20} + \alpha\,A^{19} + \beta\,A = \begin{pmatrix} 1 & 0 & 0 \\ 0 & 4 & 0 \\ 0 & 0 & 1 \end{pmatrix} for some real numbers α\alpha and eta, then βα\beta - \alpha is equal to: