1.If the matrix A=(10002030−1)A = \begin{pmatrix} 1 & 0 & 0 \\ 0 & 2 & 0 \\ 3 & 0 & -1 \end{pmatrix}A=10302000−1 satisfies the equation A20+α A19+β A=(100040001)A^{20} + \alpha\,A^{19} + \beta\,A = \begin{pmatrix} 1 & 0 & 0 \\ 0 & 4 & 0 \\ 0 & 0 & 1 \end{pmatrix}A20+αA19+βA=100040001 for some real numbers α\alphaα and eta, then β−α\beta - \alphaβ−α is equal to:a.222b.−1-1−1c.111d.444Login to continueOnly logged in users canattempt or see the solution.