1.For some λ,μ\lambda, \muλ,μ, letf(x)=∣a+sinxabaa+1+sinxbab1+b+sinx∣f(x) = \begin{vmatrix} a + \sin x & a & b \\ a & a + 1 + \sin x & b \\ a & b & 1 + b + \sin x \end{vmatrix}f(x)=a+sinxaaaa+1+sinxbbb1+b+sinxIf limx→0f(x)x=λ+μa+νb\displaystyle\lim_{x \to 0} \frac{f(x)}{x} = \lambda + \mu a + \nu bx→0limxf(x)=λ+μa+νb, then (λ+μ+ν)2(\lambda + \mu + \nu)^2(λ+μ+ν)2 is equal to:a.161616b.252525c.999d.363636Login to continueOnly logged in users canattempt or see the solution.
