1.Let z=x+iyz = x + iyz=x+iy and w=u+ivw = u + ivw=u+iv be complex numbers on the unit circle such that z2+w2=1z^2 + w^2 = 1z2+w2=1. Then the number of ordered pairs (z,w)(z, w)(z,w) isa.000b.444c.888d.infiniteLogin to continueOnly logged in users canattempt or see the solution.