1.Find the area of the triangle formed by the XXX-axis and the tangent and the normal to the curve x2a2+y2b2=1\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1a2x2+b2y2=1 at the point (a2,b2)\left(\frac{a}{\sqrt{2}}, \frac{b}{\sqrt{2}}\right)(2a,2b).a.ab4a2+b2\frac{ab}{4}\sqrt{a^2 + b^2}4aba2+b2b.4ab4ab4abc.b4a(a2+b2)\frac{b}{4a}(a^2 + b^2)4ab(a2+b2)d.ab2a2+b2\frac{ab}{2}\sqrt{a^2 + b^2}2aba2+b2Login to continueOnly logged in users canattempt or see the solution.
