1.limx→0cosax−cosbxx2\displaystyle\lim_{x\to0}\frac{\cos ax-\cos bx}{x^2}x→0limx2cosax−cosbx is equal toa.a2−b22\frac{a^2-b^2}{2}2a2−b2b.b2−a22\frac{b^2-a^2}{2}2b2−a2c.a2−b2a^2-b^2a2−b2d.b2−a2b^2-a^2b2−a2Login to continueOnly logged in users canattempt or see the solution.
