1.Let f(x)={loge(1+5x)−loge(1+ax)x,x≠010,x=0f(x) = \begin{cases} \frac{\log_e(1+5x) - \log_e(1+ax)}{x}, & x \neq 0 \\ 10, & x = 0 \end{cases}f(x)={xloge(1+5x)−loge(1+ax),10,x=0x=0 be continuous at x=0x = 0x=0. Then aaa is equal to:Login to continueOnly logged in users canattempt or see the solution.
