1.AAA and BBB are any two points on the positive xxx and yyy axis respectively satisfying 2(OA)+3(OB)=102(OA) + 3(OB) = 102(OA)+3(OB)=10. If PPP is the middle point of ABABAB, then the locus of PPP isa.2x+3y=52x + 3y = 52x+3y=5b.2x+3y=102x + 3y = 102x+3y=10c.3x+2y=53x + 2y = 53x+2y=5d.3x+2y=103x + 2y = 103x+2y=10Login to continueOnly logged in users canattempt or see the solution.